Distance from Lake Mary to Monte San Savino
The shortest distance (air line) between Lake Mary and Monte San Savino is 5,028.66 mi (8,092.85 km).
How far is Lake Mary from Monte San Savino
Lake Mary is located in Florida, United States within 28° 45' 33.12" N -82° 39' 50.4" W (28.7592, -81.3360) coordinates. The local time in Lake Mary is 01:44 (01.03.2025)
Monte San Savino is located in Arezzo, Italy within 43° 19' 59.88" N 11° 43' 59.88" E (43.3333, 11.7333) coordinates. The local time in Monte San Savino is 07:44 (01.03.2025)
The calculated flying distance from Monte San Savino to Monte San Savino is 5,028.66 miles which is equal to 8,092.85 km.
Lake Mary, Florida, United States
Related Distances from Lake Mary
Monte San Savino, Arezzo, Italy