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      Distance from Lake Mary to San Gregorio di Catania

      The shortest distance (air line) between Lake Mary and San Gregorio di Catania is 5,359.57 mi (8,625.40 km).

      How far is Lake Mary from San Gregorio di Catania

      Lake Mary is located in Florida, United States within 28° 45' 33.12" N -82° 39' 50.4" W (28.7592, -81.3360) coordinates. The local time in Lake Mary is 15:08 (02.03.2025)

      San Gregorio di Catania is located in Catania, Italy within 37° 34' 0.12" N 15° 7' 0.12" E (37.5667, 15.1167) coordinates. The local time in San Gregorio di Catania is 21:08 (02.03.2025)

      The calculated flying distance from San Gregorio di Catania to San Gregorio di Catania is 5,359.57 miles which is equal to 8,625.40 km.

      Lake Mary, Florida, United States

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      Lake Mary to Dallas (Texas)956.41 mi (1,539.20 km)
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      Lake Mary to Riverside (California)2,146.44 mi (3,454.36 km)
      Lake Mary to Los Angeles (California)2,204.27 mi (3,547.43 km)
      Lake Mary to San Francisco (California)2,434.31 mi (3,917.64 km)
      Lake Mary to Miami (Florida)216.88 mi (349.03 km)
      Lake Mary to Portland (Oregon)2,516.98 mi (4,050.69 km)
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      San Gregorio di Catania, Catania, Italy

      Related Distances to San Gregorio di Catania