Distance from Lake Mary to Sint-Andries
The shortest distance (air line) between Lake Mary and Sint-Andries is 4,470.03 mi (7,193.82 km).
How far is Lake Mary from Sint-Andries
Lake Mary is located in Florida, United States within 28° 45' 33.12" N -82° 39' 50.4" W (28.7592, -81.3360) coordinates. The local time in Lake Mary is 14:50 (23.01.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 20:50 (23.01.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,470.03 miles which is equal to 7,193.82 km.
Lake Mary, Florida, United States
Related Distances from Lake Mary
Sint-Andries, Arr. Brugge, Belgium