Distance from Lake Mary to Sint-Kruis
The shortest distance (air line) between Lake Mary and Sint-Kruis is 4,472.61 mi (7,197.97 km).
How far is Lake Mary from Sint-Kruis
Lake Mary is located in Florida, United States within 28° 45' 33.12" N -82° 39' 50.4" W (28.7592, -81.3360) coordinates. The local time in Lake Mary is 16:39 (23.01.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 22:39 (23.01.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 4,472.61 miles which is equal to 7,197.97 km.
Lake Mary, Florida, United States
Related Distances from Lake Mary
Sint-Kruis, Arr. Brugge, Belgium