Distance from Lake Monticello to Aleksandrovac
The shortest distance (air line) between Lake Monticello and Aleksandrovac is 4,889.74 mi (7,869.28 km).
How far is Lake Monticello from Aleksandrovac
Lake Monticello is located in Virginia, United States within 37° 55' 15.6" N -79° 40' 13.8" W (37.9210, -78.3295) coordinates. The local time in Lake Monticello is 12:35 (23.02.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 18:35 (23.02.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 4,889.74 miles which is equal to 7,869.28 km.
Lake Monticello, Virginia, United States
Related Distances from Lake Monticello
Aleksandrovac, Rasinska oblast, Serbia