Distance from Lake Monticello to Alexandroupoli
The shortest distance (air line) between Lake Monticello and Alexandroupoli is 5,195.01 mi (8,360.57 km).
How far is Lake Monticello from Alexandroupoli
Lake Monticello is located in Virginia, United States within 37° 55' 15.6" N -79° 40' 13.8" W (37.9210, -78.3295) coordinates. The local time in Lake Monticello is 15:29 (05.02.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 22:29 (05.02.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 5,195.01 miles which is equal to 8,360.57 km.
Lake Monticello, Virginia, United States