Distance from Lake Monticello to Drobeta-Turnu Severin
The shortest distance (air line) between Lake Monticello and Drobeta-Turnu Severin is 4,908.58 mi (7,899.59 km).
How far is Lake Monticello from Drobeta-Turnu Severin
Lake Monticello is located in Virginia, United States within 37° 55' 15.6" N -79° 40' 13.8" W (37.9210, -78.3295) coordinates. The local time in Lake Monticello is 21:44 (22.02.2025)
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 04:44 (23.02.2025)
The calculated flying distance from Drobeta-Turnu Severin to Drobeta-Turnu Severin is 4,908.58 miles which is equal to 7,899.59 km.
Lake Monticello, Virginia, United States
Related Distances from Lake Monticello
Drobeta-Turnu Severin, Mehedinţi, Romania