Distance from Lake Monticello to San Pietro in Casale
The shortest distance (air line) between Lake Monticello and San Pietro in Casale is 4,437.09 mi (7,140.81 km).
How far is Lake Monticello from San Pietro in Casale
Lake Monticello is located in Virginia, United States within 37° 55' 15.6" N -79° 40' 13.8" W (37.9210, -78.3295) coordinates. The local time in Lake Monticello is 11:42 (08.02.2025)
San Pietro in Casale is located in Bologna, Italy within 44° 42' 0" N 11° 24' 0" E (44.7000, 11.4000) coordinates. The local time in San Pietro in Casale is 17:42 (08.02.2025)
The calculated flying distance from San Pietro in Casale to San Pietro in Casale is 4,437.09 miles which is equal to 7,140.81 km.
Lake Monticello, Virginia, United States
Related Distances from Lake Monticello
San Pietro in Casale, Bologna, Italy