Distance from Lake Norman of Catawba to Asenovgrad
The shortest distance (air line) between Lake Norman of Catawba and Asenovgrad is 5,321.45 mi (8,564.05 km).
How far is Lake Norman of Catawba from Asenovgrad
Lake Norman of Catawba is located in North Carolina, United States within 35° 35' 58.2" N -81° 0' 57.6" W (35.5995, -80.9840) coordinates. The local time in Lake Norman of Catawba is 23:53 (18.02.2025)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 06:53 (19.02.2025)
The calculated flying distance from Asenovgrad to Asenovgrad is 5,321.45 miles which is equal to 8,564.05 km.
Lake Norman of Catawba, North Carolina, United States