Distance from Lake Norman of Catawba to Svilengrad
The shortest distance (air line) between Lake Norman of Catawba and Svilengrad is 5,386.61 mi (8,668.90 km).
How far is Lake Norman of Catawba from Svilengrad
Lake Norman of Catawba is located in North Carolina, United States within 35° 35' 58.2" N -81° 0' 57.6" W (35.5995, -80.9840) coordinates. The local time in Lake Norman of Catawba is 18:46 (20.02.2025)
Svilengrad is located in Haskovo, Bulgaria within 41° 46' 0.12" N 26° 11' 60" E (41.7667, 26.2000) coordinates. The local time in Svilengrad is 01:46 (21.02.2025)
The calculated flying distance from Svilengrad to Svilengrad is 5,386.61 miles which is equal to 8,668.90 km.
Lake Norman of Catawba, North Carolina, United States