Distance from Lake Oswego to Aartselaar
The shortest distance (air line) between Lake Oswego and Aartselaar is 5,058.20 mi (8,140.38 km).
How far is Lake Oswego from Aartselaar
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 04:50 (02.02.2025)
Aartselaar is located in Arr. Antwerpen, Belgium within 51° 7' 59.88" N 4° 22' 59.88" E (51.1333, 4.3833) coordinates. The local time in Aartselaar is 13:50 (02.02.2025)
The calculated flying distance from Aartselaar to Aartselaar is 5,058.20 miles which is equal to 8,140.38 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
Aartselaar, Arr. Antwerpen, Belgium