Distance from Lake Oswego to Aleksandrovac
The shortest distance (air line) between Lake Oswego and Aleksandrovac is 5,905.84 mi (9,504.53 km).
How far is Lake Oswego from Aleksandrovac
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 18:37 (27.05.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 03:37 (28.05.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,905.84 miles which is equal to 9,504.53 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
Aleksandrovac, Rasinska oblast, Serbia