Distance from Lake Oswego to Aleksandrow Lodzki
The shortest distance (air line) between Lake Oswego and Aleksandrow Lodzki is 5,348.97 mi (8,608.33 km).
How far is Lake Oswego from Aleksandrow Lodzki
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 00:34 (28.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 09:34 (28.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,348.97 miles which is equal to 8,608.33 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
Aleksandrow Lodzki, Łódzki, Poland