Distance from Lake Oswego to Bad Sassendorf
The shortest distance (air line) between Lake Oswego and Bad Sassendorf is 5,125.44 mi (8,248.59 km).
How far is Lake Oswego from Bad Sassendorf
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 10:01 (02.05.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 19:01 (02.05.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 5,125.44 miles which is equal to 8,248.59 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
Bad Sassendorf, Soest, Germany