Distance from Lake Oswego to Bolintin Vale
The shortest distance (air line) between Lake Oswego and Bolintin Vale is 5,934.70 mi (9,550.98 km).
How far is Lake Oswego from Bolintin Vale
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 21:27 (27.05.2025)
Bolintin Vale is located in Giurgiu, Romania within 44° 26' 49.92" N 25° 45' 25.92" E (44.4472, 25.7572) coordinates. The local time in Bolintin Vale is 07:27 (28.05.2025)
The calculated flying distance from Bolintin Vale to Bolintin Vale is 5,934.70 miles which is equal to 9,550.98 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
Bolintin Vale, Giurgiu, Romania