Distance from Lake Oswego to Diekirch
The shortest distance (air line) between Lake Oswego and Diekirch is 5,174.54 mi (8,327.61 km).
How far is Lake Oswego from Diekirch
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 20:42 (21.05.2025)
Diekirch is located in Luxembourg, Luxembourg within 49° 52' 5.16" N 6° 9' 24.12" E (49.8681, 6.1567) coordinates. The local time in Diekirch is 05:42 (22.05.2025)
The calculated flying distance from Diekirch to Diekirch is 5,174.54 miles which is equal to 8,327.61 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
Diekirch, Luxembourg, Luxembourg
Related Distances to Diekirch
Cities | Distance |
---|---|
Vianden to Diekirch | 5.06 mi (8.14 km) |
Mersch to Diekirch | 8.54 mi (13.75 km) |
Wiltz to Diekirch | 12.05 mi (19.39 km) |
Echternach to Diekirch | 12.43 mi (20.01 km) |
Clervaux to Diekirch | 13.71 mi (22.07 km) |
Redange-sur-Attert to Diekirch | 13.88 mi (22.33 km) |
Capellen to Diekirch | 17.16 mi (27.62 km) |
Luxembourg to Diekirch | 17.75 mi (28.57 km) |
Grevenmacher to Diekirch | 18.15 mi (29.22 km) |
Remich to Diekirch | 24.25 mi (39.03 km) |
Differdange to Diekirch | 26.67 mi (42.93 km) |
Dudelange to Diekirch | 26.79 mi (43.11 km) |
Esch-sur-Alzette to Diekirch | 26.83 mi (43.18 km) |