Distance from Lake Oswego to Drobeta-Turnu Severin
The shortest distance (air line) between Lake Oswego and Drobeta-Turnu Severin is 5,863.99 mi (9,437.19 km).
How far is Lake Oswego from Drobeta-Turnu Severin
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 03:36 (24.05.2025)
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 13:36 (24.05.2025)
The calculated flying distance from Drobeta-Turnu Severin to Drobeta-Turnu Severin is 5,863.99 miles which is equal to 9,437.19 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
Drobeta-Turnu Severin, Mehedinţi, Romania