Distance from Lake Oswego to La Puebla del Rio
The shortest distance (air line) between Lake Oswego and La Puebla del Rio is 5,499.26 mi (8,850.20 km).
How far is Lake Oswego from La Puebla del Rio
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 14:16 (04.06.2025)
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 23:16 (04.06.2025)
The calculated flying distance from La Puebla del Rio to La Puebla del Rio is 5,499.26 miles which is equal to 8,850.20 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
La Puebla del Rio, Sevilla, Spain