Distance from Lake Oswego to Waldshut-Tiengen
The shortest distance (air line) between Lake Oswego and Waldshut-Tiengen is 5,355.58 mi (8,618.98 km).
How far is Lake Oswego from Waldshut-Tiengen
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 20:52 (11.05.2025)
Waldshut-Tiengen is located in Waldshut, Germany within 47° 37' 23.16" N 8° 12' 51.84" E (47.6231, 8.2144) coordinates. The local time in Waldshut-Tiengen is 05:52 (12.05.2025)
The calculated flying distance from Waldshut-Tiengen to Waldshut-Tiengen is 5,355.58 miles which is equal to 8,618.98 km.
Lake Oswego, Oregon, United States
Related Distances from Lake Oswego
Waldshut-Tiengen, Waldshut, Germany