Distance from Lake Stickney to Sveti Ivan Zelina
The shortest distance (air line) between Lake Stickney and Sveti Ivan Zelina is 5,486.21 mi (8,829.20 km).
How far is Lake Stickney from Sveti Ivan Zelina
Lake Stickney is located in Washington, United States within 47° 52' 23.88" N -123° 44' 30.48" W (47.8733, -122.2582) coordinates. The local time in Lake Stickney is 12:32 (24.01.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 21:32 (24.01.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,486.21 miles which is equal to 8,829.20 km.
Lake Stickney, Washington, United States
Related Distances from Lake Stickney
Sveti Ivan Zelina, Zagrebačka županija, Croatia