Distance from Lake in the Hills to Svilengrad
The shortest distance (air line) between Lake in the Hills and Svilengrad is 5,349.32 mi (8,608.90 km).
How far is Lake in the Hills from Svilengrad
Lake in the Hills is located in Illinois, United States within 42° 11' 28.68" N -89° 39' 8.28" W (42.1913, -88.3477) coordinates. The local time in Lake in the Hills is 11:00 (03.02.2025)
Svilengrad is located in Haskovo, Bulgaria within 41° 46' 0.12" N 26° 11' 60" E (41.7667, 26.2000) coordinates. The local time in Svilengrad is 19:00 (03.02.2025)
The calculated flying distance from Svilengrad to Svilengrad is 5,349.32 miles which is equal to 8,608.90 km.
Lake in the Hills, Illinois, United States