Distance from Lakeville to Dimitrovgrad
The shortest distance (air line) between Lakeville and Dimitrovgrad is 5,212.08 mi (8,388.03 km).
How far is Lakeville from Dimitrovgrad
Lakeville is located in Minnesota, United States within 44° 40' 38.64" N -94° 44' 52.8" W (44.6774, -93.2520) coordinates. The local time in Lakeville is 03:50 (24.01.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 10:50 (24.01.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,212.08 miles which is equal to 8,388.03 km.
Lakeville, Minnesota, United States
Related Distances from Lakeville
Dimitrovgrad, Pirotska oblast, Serbia