Distance from Lakeville to Sajoszentpeter
The shortest distance (air line) between Lakeville and Sajoszentpeter is 4,879.48 mi (7,852.76 km).
How far is Lakeville from Sajoszentpeter
Lakeville is located in Minnesota, United States within 44° 40' 38.64" N -94° 44' 52.8" W (44.6774, -93.2520) coordinates. The local time in Lakeville is 18:31 (24.02.2025)
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 01:31 (25.02.2025)
The calculated flying distance from Sajoszentpeter to Sajoszentpeter is 4,879.48 miles which is equal to 7,852.76 km.
Lakeville, Minnesota, United States
Related Distances from Lakeville
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary