Distance from Lakewood Ranch to San Giorgio di Piano
The shortest distance (air line) between Lakewood Ranch and San Giorgio di Piano is 5,086.65 mi (8,186.17 km).
How far is Lakewood Ranch from San Giorgio di Piano
Lakewood Ranch is located in Florida, United States within 27° 25' 6.6" N -83° 36' 18.72" W (27.4185, -82.3948) coordinates. The local time in Lakewood Ranch is 15:31 (27.02.2025)
San Giorgio di Piano is located in Bologna, Italy within 44° 38' 60" N 11° 22' 59.88" E (44.6500, 11.3833) coordinates. The local time in San Giorgio di Piano is 21:31 (27.02.2025)
The calculated flying distance from San Giorgio di Piano to San Giorgio di Piano is 5,086.65 miles which is equal to 8,186.17 km.
Lakewood Ranch, Florida, United States
Related Distances from Lakewood Ranch
San Giorgio di Piano, Bologna, Italy