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      Distance from Lakewood Ranch to San Gregorio di Catania

      The shortest distance (air line) between Lakewood Ranch and San Gregorio di Catania is 5,466.58 mi (8,797.61 km).

      How far is Lakewood Ranch from San Gregorio di Catania

      Lakewood Ranch is located in Florida, United States within 27° 25' 6.6" N -83° 36' 18.72" W (27.4185, -82.3948) coordinates. The local time in Lakewood Ranch is 15:22 (27.02.2025)

      San Gregorio di Catania is located in Catania, Italy within 37° 34' 0.12" N 15° 7' 0.12" E (37.5667, 15.1167) coordinates. The local time in San Gregorio di Catania is 21:22 (27.02.2025)

      The calculated flying distance from San Gregorio di Catania to San Gregorio di Catania is 5,466.58 miles which is equal to 8,797.61 km.

      Lakewood Ranch, Florida, United States

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      San Gregorio di Catania, Catania, Italy

      Related Distances to San Gregorio di Catania