Distance from Lakewood Ranch to Sannicolau Mare
The shortest distance (air line) between Lakewood Ranch and Sannicolau Mare is 5,449.64 mi (8,770.35 km).
How far is Lakewood Ranch from Sannicolau Mare
Lakewood Ranch is located in Florida, United States within 27° 25' 6.6" N -83° 36' 18.72" W (27.4185, -82.3948) coordinates. The local time in Lakewood Ranch is 12:12 (09.03.2025)
Sannicolau Mare is located in Timiş, Romania within 46° 3' 48.96" N 20° 36' 45" E (46.0636, 20.6125) coordinates. The local time in Sannicolau Mare is 19:12 (09.03.2025)
The calculated flying distance from Sannicolau Mare to Sannicolau Mare is 5,449.64 miles which is equal to 8,770.35 km.
Lakewood Ranch, Florida, United States
Related Distances from Lakewood Ranch
Sannicolau Mare, Timiş, Romania