Distance from Las Cruces to Fontainebleau
The shortest distance (air line) between Las Cruces and Fontainebleau is 5,369.58 mi (8,641.50 km).
How far is Las Cruces from Fontainebleau
Las Cruces is located in New Mexico, United States within 32° 19' 35.4" N -107° 12' 38.52" W (32.3265, -106.7893) coordinates. The local time in Las Cruces is 10:38 (31.01.2025)
Fontainebleau is located in Seine-et-Marne, France within 48° 24' 32.04" N 2° 42' 6.12" E (48.4089, 2.7017) coordinates. The local time in Fontainebleau is 18:38 (31.01.2025)
The calculated flying distance from Fontainebleau to Fontainebleau is 5,369.58 miles which is equal to 8,641.50 km.
Las Cruces, New Mexico, United States
Related Distances from Las Cruces
Fontainebleau, Seine-et-Marne, France