Distance from Laurinburg to Bad Segeberg
The shortest distance (air line) between Laurinburg and Bad Segeberg is 4,314.94 mi (6,944.23 km).
How far is Laurinburg from Bad Segeberg
Laurinburg is located in North Carolina, United States within 34° 45' 36.72" N -80° 31' 21.72" W (34.7602, -79.4773) coordinates. The local time in Laurinburg is 19:47 (08.02.2025)
Bad Segeberg is located in Segeberg, Germany within 53° 55' 0.12" N 10° 19' 0.12" E (53.9167, 10.3167) coordinates. The local time in Bad Segeberg is 01:47 (09.02.2025)
The calculated flying distance from Bad Segeberg to Bad Segeberg is 4,314.94 miles which is equal to 6,944.23 km.
Laurinburg, North Carolina, United States
Related Distances from Laurinburg
Bad Segeberg, Segeberg, Germany