Distance from Laurinburg to Six-Fours-les-Plages
The shortest distance (air line) between Laurinburg and Six-Fours-les-Plages is 4,420.30 mi (7,113.79 km).
How far is Laurinburg from Six-Fours-les-Plages
Laurinburg is located in North Carolina, United States within 34° 45' 36.72" N -80° 31' 21.72" W (34.7602, -79.4773) coordinates. The local time in Laurinburg is 07:50 (16.03.2025)
Six-Fours-les-Plages is located in Var, France within 43° 6' 3.24" N 5° 49' 12" E (43.1009, 5.8200) coordinates. The local time in Six-Fours-les-Plages is 13:50 (16.03.2025)
The calculated flying distance from Six-Fours-les-Plages to Six-Fours-les-Plages is 4,420.30 miles which is equal to 7,113.79 km.
Laurinburg, North Carolina, United States
Related Distances from Laurinburg
Six-Fours-les-Plages, Var, France