Distance from Lawndale to Aleksandrow Kujawski
The shortest distance (air line) between Lawndale and Aleksandrow Kujawski is 5,909.75 mi (9,510.83 km).
How far is Lawndale from Aleksandrow Kujawski
Lawndale is located in California, United States within 33° 53' 18.24" N -119° 38' 48.84" W (33.8884, -118.3531) coordinates. The local time in Lawndale is 20:21 (04.03.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 05:21 (05.03.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,909.75 miles which is equal to 9,510.83 km.
Lawndale, California, United States
Related Distances from Lawndale
Aleksandrow Kujawski, Włocławski, Poland