Distance from Lawrence to Aleksandrovac
The shortest distance (air line) between Lawrence and Aleksandrovac is 5,492.94 mi (8,840.04 km).
How far is Lawrence from Aleksandrovac
Lawrence is located in Kansas, United States within 38° 57' 34.92" N -96° 44' 8.88" W (38.9597, -95.2642) coordinates. The local time in Lawrence is 13:11 (03.03.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 20:11 (03.03.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,492.94 miles which is equal to 8,840.04 km.
Lawrence, Kansas, United States
Related Distances from Lawrence
Aleksandrovac, Rasinska oblast, Serbia