Distance from Lawrence to Diepenbeek
The shortest distance (air line) between Lawrence and Diepenbeek is 4,601.72 mi (7,405.75 km).
How far is Lawrence from Diepenbeek
Lawrence is located in Kansas, United States within 38° 57' 34.92" N -96° 44' 8.88" W (38.9597, -95.2642) coordinates. The local time in Lawrence is 00:16 (09.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 07:16 (09.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,601.72 miles which is equal to 7,405.75 km.
Lawrence, Kansas, United States
Related Distances from Lawrence
Diepenbeek, Arr. Hasselt, Belgium