Distance from Lawrence to Dimitrovgrad
The shortest distance (air line) between Lawrence and Dimitrovgrad is 5,575.73 mi (8,973.27 km).
How far is Lawrence from Dimitrovgrad
Lawrence is located in Kansas, United States within 38° 57' 34.92" N -96° 44' 8.88" W (38.9597, -95.2642) coordinates. The local time in Lawrence is 09:38 (03.02.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 16:38 (03.02.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,575.73 miles which is equal to 8,973.27 km.
Lawrence, Kansas, United States
Related Distances from Lawrence
Dimitrovgrad, Pirotska oblast, Serbia