Distance from Leawood to Aleksandrow Kujawski
The shortest distance (air line) between Leawood and Aleksandrow Kujawski is 4,950.34 mi (7,966.80 km).
How far is Leawood from Aleksandrow Kujawski
Leawood is located in Kansas, United States within 38° 54' 27" N -95° 22' 27.12" W (38.9075, -94.6258) coordinates. The local time in Leawood is 17:26 (06.03.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:26 (07.03.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,950.34 miles which is equal to 7,966.80 km.
Leawood, Kansas, United States
Related Distances from Leawood
Aleksandrow Kujawski, Włocławski, Poland