Distance from Lenexa to Aleksandrow Kujawski
The shortest distance (air line) between Lenexa and Aleksandrow Kujawski is 4,952.86 mi (7,970.86 km).
How far is Lenexa from Aleksandrow Kujawski
Lenexa is located in Kansas, United States within 38° 57' 39.24" N -95° 11' 53.52" W (38.9609, -94.8018) coordinates. The local time in Lenexa is 12:34 (04.03.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 19:34 (04.03.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,952.86 miles which is equal to 7,970.86 km.
Related Distances from Lenexa
Aleksandrow Kujawski, Włocławski, Poland