Distance from Lenexa to Aleksandrow Lodzki
The shortest distance (air line) between Lenexa and Aleksandrow Lodzki is 5,020.65 mi (8,079.95 km).
How far is Lenexa from Aleksandrow Lodzki
Lenexa is located in Kansas, United States within 38° 57' 39.24" N -95° 11' 53.52" W (38.9609, -94.8018) coordinates. The local time in Lenexa is 12:09 (04.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 19:09 (04.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,020.65 miles which is equal to 8,079.95 km.
Related Distances from Lenexa
Aleksandrow Lodzki, Łódzki, Poland