Distance from Lenoir to Aleksandrovac
The shortest distance (air line) between Lenoir and Aleksandrovac is 5,114.00 mi (8,230.18 km).
How far is Lenoir from Aleksandrovac
Lenoir is located in North Carolina, United States within 35° 54' 33.84" N -82° 28' 30.36" W (35.9094, -81.5249) coordinates. The local time in Lenoir is 06:23 (10.10.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 12:23 (10.10.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,114.00 miles which is equal to 8,230.18 km.
Lenoir, North Carolina, United States
Related Distances from Lenoir
Aleksandrovac, Rasinska oblast, Serbia