Distance from Lenoir to Bad Segeberg
The shortest distance (air line) between Lenoir and Bad Segeberg is 4,332.10 mi (6,971.84 km).
How far is Lenoir from Bad Segeberg
Lenoir is located in North Carolina, United States within 35° 54' 33.84" N -82° 28' 30.36" W (35.9094, -81.5249) coordinates. The local time in Lenoir is 18:26 (22.02.2025)
Bad Segeberg is located in Segeberg, Germany within 53° 55' 0.12" N 10° 19' 0.12" E (53.9167, 10.3167) coordinates. The local time in Bad Segeberg is 00:26 (23.02.2025)
The calculated flying distance from Bad Segeberg to Bad Segeberg is 4,332.10 miles which is equal to 6,971.84 km.
Lenoir, North Carolina, United States
Related Distances from Lenoir
Bad Segeberg, Segeberg, Germany