Distance from Lenoir to Sajoszentpeter
The shortest distance (air line) between Lenoir and Sajoszentpeter is 4,916.81 mi (7,912.84 km).
How far is Lenoir from Sajoszentpeter
Lenoir is located in North Carolina, United States within 35° 54' 33.84" N -82° 28' 30.36" W (35.9094, -81.5249) coordinates. The local time in Lenoir is 17:14 (28.02.2025)
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 23:14 (28.02.2025)
The calculated flying distance from Sajoszentpeter to Sajoszentpeter is 4,916.81 miles which is equal to 7,912.84 km.
Lenoir, North Carolina, United States
Related Distances from Lenoir
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary