Distance from Lenoir to Six-Fours-les-Plages
The shortest distance (air line) between Lenoir and Six-Fours-les-Plages is 4,466.89 mi (7,188.76 km).
How far is Lenoir from Six-Fours-les-Plages
Lenoir is located in North Carolina, United States within 35° 54' 33.84" N -82° 28' 30.36" W (35.9094, -81.5249) coordinates. The local time in Lenoir is 19:00 (18.02.2025)
Six-Fours-les-Plages is located in Var, France within 43° 6' 3.24" N 5° 49' 12" E (43.1009, 5.8200) coordinates. The local time in Six-Fours-les-Plages is 01:00 (19.02.2025)
The calculated flying distance from Six-Fours-les-Plages to Six-Fours-les-Plages is 4,466.89 miles which is equal to 7,188.76 km.
Lenoir, North Carolina, United States
Related Distances from Lenoir
Six-Fours-les-Plages, Var, France