Distance from Leopoldshohe to Sendenhorst
The shortest distance (air line) between Leopoldshohe and Sendenhorst is 39.03 mi (62.81 km).
How far is Leopoldshohe from Sendenhorst
Leopoldshohe is located in Lippe, Germany within 52° 1' 0.12" N 8° 41' 60" E (52.0167, 8.7000) coordinates. The local time in Leopoldshohe is 13:22 (11.05.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 13:22 (11.05.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 39.03 miles which is equal to 62.81 km.
Related Distances from Leopoldshohe
Sendenhorst, Warendorf, Germany