Distance from Lexington to Diepenbeek
The shortest distance (air line) between Lexington and Diepenbeek is 4,239.34 mi (6,822.55 km).
How far is Lexington from Diepenbeek
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 11:46 (23.01.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 17:46 (23.01.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,239.34 miles which is equal to 6,822.55 km.
Lexington, Kentucky, United States
Related Distances from Lexington
Diepenbeek, Arr. Hasselt, Belgium