Distance from Lexington to Dimitrovgrad
The shortest distance (air line) between Lexington and Dimitrovgrad is 5,219.21 mi (8,399.50 km).
How far is Lexington from Dimitrovgrad
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 08:10 (24.01.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 14:10 (24.01.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,219.21 miles which is equal to 8,399.50 km.
Lexington, Kentucky, United States
Related Distances from Lexington
Dimitrovgrad, Pirotska oblast, Serbia