Distance from Lexington to Sint-Amandsberg
The shortest distance (air line) between Lexington and Sint-Amandsberg is 4,169.52 mi (6,710.20 km).
How far is Lexington from Sint-Amandsberg
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 00:03 (24.01.2025)
Sint-Amandsberg is located in Arr. Gent, Belgium within 51° 3' 14.04" N 3° 44' 57.12" E (51.0539, 3.7492) coordinates. The local time in Sint-Amandsberg is 06:03 (24.01.2025)
The calculated flying distance from Sint-Amandsberg to Sint-Amandsberg is 4,169.52 miles which is equal to 6,710.20 km.
Lexington, Kentucky, United States
Related Distances from Lexington
Sint-Amandsberg, Arr. Gent, Belgium