Distance from Lexington to Sint-Andries
The shortest distance (air line) between Lexington and Sint-Andries is 4,143.01 mi (6,667.54 km).
How far is Lexington from Sint-Andries
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 00:12 (24.01.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 06:12 (24.01.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,143.01 miles which is equal to 6,667.54 km.
Lexington, Kentucky, United States
Related Distances from Lexington
Sint-Andries, Arr. Brugge, Belgium