Distance from Lexington to Sint-Katelijne-Waver
The shortest distance (air line) between Lexington and Sint-Katelijne-Waver is 4,199.93 mi (6,759.13 km).
How far is Lexington from Sint-Katelijne-Waver
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 00:22 (24.01.2025)
Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 06:22 (24.01.2025)
The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 4,199.93 miles which is equal to 6,759.13 km.
Lexington, Kentucky, United States
Related Distances from Lexington
Sint-Katelijne-Waver, Arr. Mechelen, Belgium