Distance from Lexington Park to Aci Castello
The shortest distance (air line) between Lexington Park and Aci Castello is 4,759.98 mi (7,660.45 km).
How far is Lexington Park from Aci Castello
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 18:47 (28.02.2025)
Aci Castello is located in Catania, Italy within 37° 33' 20.16" N 15° 8' 44.88" E (37.5556, 15.1458) coordinates. The local time in Aci Castello is 00:47 (01.03.2025)
The calculated flying distance from Aci Castello to Aci Castello is 4,759.98 miles which is equal to 7,660.45 km.
Lexington Park, Maryland, United States