Distance from Lexington Park to Agia Varvara
The shortest distance (air line) between Lexington Park and Agia Varvara is 5,124.84 mi (8,247.64 km).
How far is Lexington Park from Agia Varvara
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 12:42 (27.02.2025)
Agia Varvara is located in Dytikos Tomeas Athinon, Greece within 38° 0' 0" N 23° 38' 60" E (38.0000, 23.6500) coordinates. The local time in Agia Varvara is 19:42 (27.02.2025)
The calculated flying distance from Agia Varvara to Agia Varvara is 5,124.84 miles which is equal to 8,247.64 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Agia Varvara, Dytikos Tomeas Athinon, Greece