Distance from Lexington Park to Aleksandrow Lodzki
The shortest distance (air line) between Lexington Park and Aleksandrow Lodzki is 4,423.27 mi (7,118.56 km).
How far is Lexington Park from Aleksandrow Lodzki
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 12:38 (11.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 18:38 (11.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,423.27 miles which is equal to 7,118.56 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Aleksandrow Lodzki, Łódzki, Poland