Distance from Lexington Park to Bad Sassendorf
The shortest distance (air line) between Lexington Park and Bad Sassendorf is 4,002.64 mi (6,441.63 km).
How far is Lexington Park from Bad Sassendorf
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 00:01 (23.02.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 06:01 (23.02.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,002.64 miles which is equal to 6,441.63 km.
Lexington Park, Maryland, United States
Related Distances from Lexington Park
Bad Sassendorf, Soest, Germany